Base | Representation |
---|---|
bin | 1011100011100110… |
… | …0111011001000100 |
3 | 22000012011120201010 |
4 | 2320321213121010 |
5 | 22323120030200 |
6 | 1231453002220 |
7 | 136605340161 |
oct | 27071473104 |
9 | 8005146633 |
10 | 3102111300 |
11 | 1352074152 |
12 | 726a83370 |
13 | 3a58b7022 |
14 | 215dc7068 |
15 | 132514150 |
hex | b8e67644 |
3102111300 has 72 divisors (see below), whose sum is σ = 9009798336. Its totient is φ = 824063360.
The previous prime is 3102111293. The next prime is 3102111367. The reversal of 3102111300 is 31112013.
3102111300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 59242 + ... + 98558.
It is an arithmetic number, because the mean of its divisors is an integer number (125136088).
Almost surely, 23102111300 is an apocalyptic number.
3102111300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3102111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4504899168).
3102111300 is an abundant number, since it is smaller than the sum of its proper divisors (5907687036).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3102111300 is a wasteful number, since it uses less digits than its factorization.
3102111300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39597 (or 39590 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
The square root of 3102111300 is about 55696.6004348560. The cubic root of 3102111300 is about 1458.4306807035.
Adding to 3102111300 its reverse (31112013), we get a palindrome (3133223313).
The spelling of 3102111300 in words is "three billion, one hundred two million, one hundred eleven thousand, three hundred".
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