3110013130112 has 64 divisors (see below), whose sum is σ = 7090574749440. Its totient is φ = 1331029117440.

The previous prime is 3110013130111. The next prime is 3110013130123. The reversal of 3110013130112 is 2110313100113.

It is a tau number, because it is divible by the number of its divisors (64).

It is a super-2 number, since 2×3110013130112² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3110013130111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1735814 + ... + 3038597.

It is an arithmetic number, because the mean of its divisors is an integer number (110790230460).

Almost surely, 2^{3110013130112} is an apocalyptic number.

3110013130112 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

3110013130112 is an abundant number, since it is smaller than the sum of its proper divisors (3980561619328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3110013130112 is an equidigital number, since it uses as much as digits as its factorization.

3110013130112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4775159 (or 4775147 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 3110013130112 its reverse (2110313100113), we get a palindrome (5220326230225).

Subtracting from 3110013130112 its reverse (2110313100113), we obtain a cube (999700029999 = 9999³).

The spelling of 3110013130112 in words is "three trillion, one hundred ten billion, thirteen million, one hundred thirty thousand, one hundred twelve".