Base | Representation |
---|---|
bin | 1110001001101111110110… |
… | …10010110000001001101000 |
3 | 11002012011101201000110122120 |
4 | 13010313323102300021220 |
5 | 13034342312014302202 |
6 | 150104523504551240 |
7 | 6361302454540212 |
oct | 704677322601150 |
9 | 132164351013576 |
10 | 31121254056552 |
11 | 9a094a4649340 |
12 | 35a7611022520 |
13 | 144994c66223a |
14 | 7983c34db5b2 |
15 | 38e80665d0bc |
hex | 1c4dfb4b0268 |
31121254056552 has 64 divisors (see below), whose sum is σ = 84951326404800. Its totient is φ = 9422329827840.
The previous prime is 31121254056551. The next prime is 31121254056569. The reversal of 31121254056552 is 25565045212113.
It is a happy number.
It is a super-2 number, since 2×311212540565522 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31121254056551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51909003 + ... + 52505114.
It is an arithmetic number, because the mean of its divisors is an integer number (1327364475075).
Almost surely, 231121254056552 is an apocalyptic number.
It is an amenable number.
31121254056552 is an abundant number, since it is smaller than the sum of its proper divisors (53830072348248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31121254056552 is a wasteful number, since it uses less digits than its factorization.
31121254056552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104415266 (or 104415262 counting only the distinct ones).
The product of its (nonzero) digits is 360000, while the sum is 42.
Adding to 31121254056552 its reverse (25565045212113), we get a palindrome (56686299268665).
The spelling of 31121254056552 in words is "thirty-one trillion, one hundred twenty-one billion, two hundred fifty-four million, fifty-six thousand, five hundred fifty-two".
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