Base | Representation |
---|---|
bin | 1110001010000011111011… |
… | …10001100011010011111100 |
3 | 11002020012012220200202201210 |
4 | 13011001331301203103330 |
5 | 13040031400433244400 |
6 | 150113505241204420 |
7 | 6362133542115666 |
oct | 705017561432374 |
9 | 132205186622653 |
10 | 31132033103100 |
11 | 9a13026092576 |
12 | 35a971aa90710 |
13 | 144a9798771a7 |
14 | 798b26cd3536 |
15 | 38ec37b04950 |
hex | 1c507dc634fc |
31132033103100 has 72 divisors (see below), whose sum is σ = 90240021157888. Its totient is φ = 8286698347200.
The previous prime is 31132033103089. The next prime is 31132033103131. The reversal of 31132033103100 is 130133023113.
It is a super-2 number, since 2×311320331031002 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 94692796 + ... + 95020995.
Almost surely, 231132033103100 is an apocalyptic number.
31132033103100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31132033103100 is an abundant number, since it is smaller than the sum of its proper divisors (59107988054788).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31132033103100 is a wasteful number, since it uses less digits than its factorization.
31132033103100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189714355 (or 189714348 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 31132033103100 its reverse (130133023113), we get a palindrome (31262166126213).
The spelling of 31132033103100 in words is "thirty-one trillion, one hundred thirty-two billion, thirty-three million, one hundred three thousand, one hundred".
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