Base | Representation |
---|---|
bin | 100011011001001110011000… |
… | …1010001110010001111111000 |
3 | 1111211022212110102202021210002 |
4 | 1012302130301101302033320 |
5 | 311301313042002143000 |
6 | 3022051025545212132 |
7 | 122401600426166366 |
oct | 10662346121621770 |
9 | 1454285412667702 |
10 | 311330121131000 |
11 | 902213aa023224 |
12 | 2ab01a43791048 |
13 | 104943c5b514ba |
14 | 56c465b68a636 |
15 | 25ed626c7b8d5 |
hex | 11b27314723f8 |
311330121131000 has 64 divisors (see below), whose sum is σ = 766855245780000. Its totient is φ = 117977730105600.
The previous prime is 311330121130999. The next prime is 311330121131033. The reversal of 311330121131000 is 131121033113.
It is a super-2 number, since 2×3113301211310002 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8192878925 + ... + 8192916924.
Almost surely, 2311330121131000 is an apocalyptic number.
It is an amenable number.
311330121131000 is an abundant number, since it is smaller than the sum of its proper divisors (455525124649000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311330121131000 is a wasteful number, since it uses less digits than its factorization.
311330121131000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16385795889 (or 16385795875 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 311330121131000 its reverse (131121033113), we get a palindrome (311461242164113).
The spelling of 311330121131000 in words is "three hundred eleven trillion, three hundred thirty billion, one hundred twenty-one million, one hundred thirty-one thousand".
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