Base | Representation |
---|---|
bin | 100011100001000110101100… |
… | …1000011000111110010100000 |
3 | 1111222011101212111102221101112 |
4 | 1013002031121003013302200 |
5 | 311422034032223244204 |
6 | 3024240334524322452 |
7 | 122543050232632040 |
oct | 10702153103076240 |
9 | 1458141774387345 |
10 | 312413120134304 |
11 | 905a97297a4822 |
12 | 2b0579099a3428 |
13 | 1054257a6777c7 |
14 | 5720c38c95720 |
15 | 261b8aee0a26e |
hex | 11c23590c7ca0 |
312413120134304 has 96 divisors (see below), whose sum is σ = 727996532207616. Its totient is φ = 129196914819840.
The previous prime is 312413120134301. The next prime is 312413120134321. The reversal of 312413120134304 is 403431021314213.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is not an unprimeable number, because it can be changed into a prime (312413120134301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 208227854 + ... + 209722829.
It is an arithmetic number, because the mean of its divisors is an integer number (7583297210496).
Almost surely, 2312413120134304 is an apocalyptic number.
It is an amenable number.
312413120134304 is an abundant number, since it is smaller than the sum of its proper divisors (415583412073312).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312413120134304 is a wasteful number, since it uses less digits than its factorization.
312413120134304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 417950818 (or 417950810 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 312413120134304 its reverse (403431021314213), we get a palindrome (715844141448517).
The spelling of 312413120134304 in words is "three hundred twelve trillion, four hundred thirteen billion, one hundred twenty million, one hundred thirty-four thousand, three hundred four".
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