Base | Representation |
---|---|
bin | 1110001101100011011010… |
… | …00010101000101011010100 |
3 | 11002122122220102010110001212 |
4 | 13012301231002220223110 |
5 | 13044013104413000030 |
6 | 150244550441440552 |
7 | 6403611656220662 |
oct | 706615502505324 |
9 | 132578812113055 |
10 | 31252011453140 |
11 | 9a599a37aa765 |
12 | 3608a234a0158 |
13 | 145908a42111a |
14 | 7a0869401c32 |
15 | 392e0ac30595 |
hex | 1c6c6d0a8ad4 |
31252011453140 has 24 divisors (see below), whose sum is σ = 69083393739360. Its totient is φ = 11842867497888.
The previous prime is 31252011453133. The next prime is 31252011453163. The reversal of 31252011453140 is 4135411025213.
It is a junction number, because it is equal to n+sod(n) for n = 31252011453097 and 31252011453106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41121067322 + ... + 41121068081.
It is an arithmetic number, because the mean of its divisors is an integer number (2878474739140).
Almost surely, 231252011453140 is an apocalyptic number.
It is an amenable number.
31252011453140 is an abundant number, since it is smaller than the sum of its proper divisors (37831382286220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31252011453140 is a wasteful number, since it uses less digits than its factorization.
31252011453140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82242135431 (or 82242135429 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 31252011453140 its reverse (4135411025213), we get a palindrome (35387422478353).
The spelling of 31252011453140 in words is "thirty-one trillion, two hundred fifty-two billion, eleven million, four hundred fifty-three thousand, one hundred forty".
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