Base | Representation |
---|---|
bin | 1110001111010001110111… |
… | …00001000110110101011010 |
3 | 11002212022222001000221210220 |
4 | 13013220323201012311122 |
5 | 13101001030342403310 |
6 | 150332114534020510 |
7 | 6411111311462310 |
oct | 707507341066532 |
9 | 132768861027726 |
10 | 31311310122330 |
11 | 9a82063309587 |
12 | 36184124a7736 |
13 | 146184a794264 |
14 | 7a3692a920b0 |
15 | 39472baeb670 |
hex | 1c7a3b846d5a |
31311310122330 has 64 divisors (see below), whose sum is σ = 85890965545728. Its totient is φ = 7156161308160.
The previous prime is 31311310122319. The next prime is 31311310122413. The reversal of 31311310122330 is 3322101311313.
It is a self number, because there is not a number n which added to its sum of digits gives 31311310122330.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5266851 + ... + 9505910.
It is an arithmetic number, because the mean of its divisors is an integer number (1342046336652).
Almost surely, 231311310122330 is an apocalyptic number.
31311310122330 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31311310122330 is an abundant number, since it is smaller than the sum of its proper divisors (54579655423398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31311310122330 is a wasteful number, since it uses less digits than its factorization.
31311310122330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14782871.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 31311310122330 its reverse (3322101311313), we get a palindrome (34633411433643).
The spelling of 31311310122330 in words is "thirty-one trillion, three hundred eleven billion, three hundred ten million, one hundred twenty-two thousand, three hundred thirty".
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