Base | Representation |
---|---|
bin | 100011100111000100011111… |
… | …0111101011110101110010100 |
3 | 1112002001210011210221122001120 |
4 | 1013032020332331132232110 |
5 | 312024002211411420200 |
6 | 3030105132521523540 |
7 | 122656224161001414 |
oct | 10716107675365624 |
9 | 1462053153848046 |
10 | 313233021201300 |
11 | 90895418555722 |
12 | 2b16a7a90435b0 |
13 | 105a199366cb65 |
14 | 574c7b830c644 |
15 | 2632d9a4249a0 |
hex | 11ce23ef5eb94 |
313233021201300 has 36 divisors (see below), whose sum is σ = 906287541343296. Its totient is φ = 83528805653600.
The previous prime is 313233021201293. The next prime is 313233021201313. The reversal of 313233021201300 is 3102120332313.
It is a super-2 number, since 2×3132330212013002 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 522055035036 + ... + 522055035635.
Almost surely, 2313233021201300 is an apocalyptic number.
313233021201300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
313233021201300 is an abundant number, since it is smaller than the sum of its proper divisors (593054520141996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313233021201300 is a wasteful number, since it uses less digits than its factorization.
313233021201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1044110070688 (or 1044110070681 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 313233021201300 its reverse (3102120332313), we get a palindrome (316335141533613).
The spelling of 313233021201300 in words is "three hundred thirteen trillion, two hundred thirty-three billion, twenty-one million, two hundred one thousand, three hundred".
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