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31520421022021 is a prime number
BaseRepresentation
bin1110010101010111010110…
…11111111000100101000101
311010121022201100002022002121
413022223223133320211011
513112412310240201041
6151012140450205541
76432163263010141
oct712535337704505
9133538640068077
1031520421022021
11a05280aa27548
123650a512838b1
131478494522429
147ad84cbb6221
15399db9d567d1
hex1caaeb7f8945

31520421022021 has 2 divisors, whose sum is σ = 31520421022022. Its totient is φ = 31520421022020.

The previous prime is 31520421022019. The next prime is 31520421022043. The reversal of 31520421022021 is 12022012402513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31519679549121 + 741472900 = 5614239^2 + 27230^2 .

It is a cyclic number.

It is not a de Polignac number, because 31520421022021 - 21 = 31520421022019 is a prime.

Together with 31520421022019, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31520421022061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15760210511010 + 15760210511011.

It is an arithmetic number, because the mean of its divisors is an integer number (15760210511011).

Almost surely, 231520421022021 is an apocalyptic number.

It is an amenable number.

31520421022021 is a deficient number, since it is larger than the sum of its proper divisors (1).

31520421022021 is an equidigital number, since it uses as much as digits as its factorization.

31520421022021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 31520421022021 its reverse (12022012402513), we get a palindrome (43542433424534).

The spelling of 31520421022021 in words is "thirty-one trillion, five hundred twenty billion, four hundred twenty-one million, twenty-two thousand, twenty-one".