Base | Representation |
---|---|
bin | 1111000001010101110001… |
… | …11011110101101000000010 |
3 | 11022221202211010212021112110 |
4 | 13200222320323311220002 |
5 | 13312141302201401010 |
6 | 154130225523240150 |
7 | 6646303625423604 |
oct | 740527073655002 |
9 | 138852733767473 |
10 | 33031401200130 |
11 | a5855a193a1a3 |
12 | 3855859519056 |
13 | 1557b03713038 |
14 | 822a2a833174 |
15 | 3c4351177120 |
hex | 1e0ab8ef5a02 |
33031401200130 has 64 divisors (see below), whose sum is σ = 80591770368000. Its totient is φ = 8662166411520.
The previous prime is 33031401200093. The next prime is 33031401200201. The reversal of 33031401200130 is 3100210413033.
It is a junction number, because it is equal to n+sod(n) for n = 33031401200097 and 33031401200106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6901576 + ... + 10662764.
It is an arithmetic number, because the mean of its divisors is an integer number (1259246412000).
Almost surely, 233031401200130 is an apocalyptic number.
33031401200130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
33031401200130 is an abundant number, since it is smaller than the sum of its proper divisors (47560369167870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33031401200130 is a wasteful number, since it uses less digits than its factorization.
33031401200130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3766059.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 33031401200130 its reverse (3100210413033), we get a palindrome (36131611613163).
The spelling of 33031401200130 in words is "thirty-three trillion, thirty-one billion, four hundred one million, two hundred thousand, one hundred thirty".
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