Base | Representation |
---|---|
bin | 100101101001010010011011… |
… | …0101111011011010111000010 |
3 | 1121102102201102212121210211010 |
4 | 1023102210312233123113002 |
5 | 321400213231034202320 |
6 | 3132131005534501350 |
7 | 126514232245654002 |
oct | 11322446657332702 |
9 | 1542381385553733 |
10 | 331130012022210 |
11 | 965654a4277005 |
12 | 3117b26b064856 |
13 | 1129c57033354b |
14 | 5baaac7144002 |
15 | 28436b8cd9ae0 |
hex | 12d2936bdb5c2 |
331130012022210 has 64 divisors (see below), whose sum is σ = 836567029555200. Its totient is φ = 83651092592832.
The previous prime is 331130012022181. The next prime is 331130012022239. The reversal of 331130012022210 is 12220210031133.
It is an interprime number because it is at equal distance from previous prime (331130012022181) and next prime (331130012022239).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7298911 + ... + 26749469.
It is an arithmetic number, because the mean of its divisors is an integer number (13071359836800).
Almost surely, 2331130012022210 is an apocalyptic number.
331130012022210 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
331130012022210 is an abundant number, since it is smaller than the sum of its proper divisors (505437017532990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331130012022210 is a wasteful number, since it uses less digits than its factorization.
331130012022210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19480455.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 331130012022210 its reverse (12220210031133), we get a palindrome (343350222053343).
The spelling of 331130012022210 in words is "three hundred thirty-one trillion, one hundred thirty billion, twelve million, twenty-two thousand, two hundred ten".
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