Base | Representation |
---|---|
bin | 110000100110101101101… |
… | …011011100110001011000 |
3 | 102211022101112220000010112 |
4 | 300212231223130301120 |
5 | 414211012434444100 |
6 | 11034231120303452 |
7 | 463212606530132 |
oct | 60465553346130 |
9 | 12738345800115 |
10 | 3340103437400 |
11 | 1078591350074 |
12 | 45b401a71b88 |
13 | 1b2c7cc89312 |
14 | b793a250052 |
15 | 5bd3ca1cb35 |
hex | 309adadcc58 |
3340103437400 has 48 divisors (see below), whose sum is σ = 8033524660800. Its totient is φ = 1289970980480.
The previous prime is 3340103437361. The next prime is 3340103437423. The reversal of 3340103437400 is 47343010433.
3340103437400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×33401034374002 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 287934152 + ... + 287945751.
It is an arithmetic number, because the mean of its divisors is an integer number (167365097100).
Almost surely, 23340103437400 is an apocalyptic number.
It is an amenable number.
3340103437400 is an abundant number, since it is smaller than the sum of its proper divisors (4693421223400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3340103437400 is a wasteful number, since it uses less digits than its factorization.
3340103437400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 575879948 (or 575879939 counting only the distinct ones).
The product of its (nonzero) digits is 36288, while the sum is 32.
Adding to 3340103437400 its reverse (47343010433), we get a palindrome (3387446447833).
The spelling of 3340103437400 in words is "three trillion, three hundred forty billion, one hundred three million, four hundred thirty-seven thousand, four hundred".
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