Base | Representation |
---|---|
bin | 1100011100010110… |
… | …1010110100110010 |
3 | 22121210002022022120 |
4 | 3013011222310302 |
5 | 23320034331424 |
6 | 1311235015110 |
7 | 145525552545 |
oct | 30705526462 |
9 | 8553068276 |
10 | 3340152114 |
11 | 14644797a2 |
12 | 79273a496 |
13 | 413000190 |
14 | 23986c85c |
15 | 148384a79 |
hex | c716ad32 |
3340152114 has 64 divisors (see below), whose sum is σ = 7355069568. Its totient is φ = 1004889600.
The previous prime is 3340152103. The next prime is 3340152119. The reversal of 3340152114 is 4112510433.
It is a happy number.
3340152114 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×33401521142 = 22313232289317337992, which contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (3340152119) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1367134 + ... + 1369574.
It is an arithmetic number, because the mean of its divisors is an integer number (114922962).
Almost surely, 23340152114 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3340152114, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3677534784).
3340152114 is an abundant number, since it is smaller than the sum of its proper divisors (4014917454).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3340152114 is a wasteful number, since it uses less digits than its factorization.
3340152114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2843.
The product of its (nonzero) digits is 1440, while the sum is 24.
The square root of 3340152114 is about 57794.0491227254. The cubic root of 3340152114 is about 1494.8194789543.
Adding to 3340152114 its reverse (4112510433), we get a palindrome (7452662547).
The spelling of 3340152114 in words is "three billion, three hundred forty million, one hundred fifty-two thousand, one hundred fourteen".
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