3340331341 has 2 divisors, whose sum is σ = 3340331342. Its totient is φ = 3340331340.

The previous prime is 3340331339. The next prime is 3340331369. The reversal of 3340331341 is 1431330433.

It is a happy number.

3340331341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2598858441 + 741472900 = 50979^2 + 27230^2 .

It is a cyclic number.

It is not a de Polignac number, because 3340331341 - 2¹ = 3340331339 is a prime.

It is a super-2 number, since 2×3340331341² = 22315626935333716562, which contains 22 as substring.

Together with 3340331339, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3340331311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670165670 + 1670165671.

It is an arithmetic number, because the mean of its divisors is an integer number (1670165671).

Almost surely, 2^3340331341 is an apocalyptic number.

It is an amenable number.

3340331341 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340331341 is an equidigital number, since it uses as much as digits as its factorization.

3340331341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

The square root of 3340331341 is about 57795.5996681408. The cubic root of 3340331341 is about 1494.8462149840.

Adding to 3340331341 its reverse (1431330433), we get a palindrome (4771661774).

The spelling of 3340331341 in words is "three billion, three hundred forty million, three hundred thirty-one thousand, three hundred forty-one".