Base | Representation |
---|---|
bin | 100011101110111010… |
… | …000101001110101110 |
3 | 10200000221001101012020 |
4 | 203232322011032232 |
5 | 1112034143112200 |
6 | 25343114051010 |
7 | 2525536056621 |
oct | 435672051656 |
9 | 120027041166 |
10 | 38367941550 |
11 | 152a9780404 |
12 | 7529419a66 |
13 | 3805c038c3 |
14 | 1bdd92ddb8 |
15 | ee85a3ea0 |
hex | 8eee853ae |
38367941550 has 48 divisors (see below), whose sum is σ = 95878899072. Its totient is φ = 10153343200.
The previous prime is 38367941539. The next prime is 38367941567. The reversal of 38367941550 is 5514976383.
It is a super-4 number, since 4×383679415504 (a number of 43 digits) contains 4444 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 38367941493 and 38367941502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 956634 + ... + 995933.
It is an arithmetic number, because the mean of its divisors is an integer number (1997477064).
Almost surely, 238367941550 is an apocalyptic number.
38367941550 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
38367941550 is an abundant number, since it is smaller than the sum of its proper divisors (57510957522).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
38367941550 is a wasteful number, since it uses less digits than its factorization.
38367941550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1952713 (or 1952708 counting only the distinct ones).
The product of its (nonzero) digits is 2721600, while the sum is 51.
The spelling of 38367941550 in words is "thirty-eight billion, three hundred sixty-seven million, nine hundred forty-one thousand, five hundred fifty".
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