411141414214031 has 2 divisors, whose sum is σ = 411141414214032. Its totient is φ = 411141414214030.

The previous prime is 411141414214009. The next prime is 411141414214033. The reversal of 411141414214031 is 130412414141114.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411141414214031 - 2²² = 411141410019727 is a prime.

It is a super-2 number, since 2×411141414214031² (a number of 30 digits) contains 22 as substring.

Together with 411141414214033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411141414214033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205570707107015 + 205570707107016.

It is an arithmetic number, because the mean of its divisors is an integer number (205570707107016).

Almost surely, 2^{411141414214031} is an apocalyptic number.

411141414214031 is a deficient number, since it is larger than the sum of its proper divisors (1).

411141414214031 is an equidigital number, since it uses as much as digits as its factorization.

411141414214031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 32.

Adding to 411141414214031 its reverse (130412414141114), we get a palindrome (541553828355145).

The spelling of 411141414214031 in words is "four hundred eleven trillion, one hundred forty-one billion, four hundred fourteen million, two hundred fourteen thousand, thirty-one".