Base | Representation |
---|---|
bin | 10010101101001100011110… |
… | …01111100011001100100000 |
3 | 12101122111102010121012210021 |
4 | 21112212033033203030200 |
5 | 20342430101040341000 |
6 | 223253144230443224 |
7 | 11443633130320303 |
oct | 1126461717431440 |
9 | 171574363535707 |
10 | 41135305012000 |
11 | 1211a426314131 |
12 | 474436a503514 |
13 | 19c507282a884 |
14 | a22d607a8b3a |
15 | 4b5054dec11a |
hex | 25698f3e3320 |
41135305012000 has 96 divisors (see below), whose sum is σ = 101083695672960. Its totient is φ = 16451801900800.
The previous prime is 41135305011953. The next prime is 41135305012019. The reversal of 41135305012000 is 21050353114.
It is a happy number.
It is a super-2 number, since 2×411353050120002 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27786531 + ... + 29229469.
It is an arithmetic number, because the mean of its divisors is an integer number (1052955163260).
Almost surely, 241135305012000 is an apocalyptic number.
41135305012000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 41135305012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (50541847836480).
41135305012000 is an abundant number, since it is smaller than the sum of its proper divisors (59948390660960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41135305012000 is a wasteful number, since it uses less digits than its factorization.
41135305012000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1450091 (or 1450073 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 41135305012000 its reverse (21050353114), we get a palindrome (41156355365114).
The spelling of 41135305012000 in words is "forty-one trillion, one hundred thirty-five billion, three hundred five million, twelve thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •