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413412100000 = 255537111733
BaseRepresentation
bin1100000010000010100…
…10000000011110100000
31110112002101210122101021
412001001102000132200
523233131444200000
6513530252015224
741603510604244
oct6010122003640
91415071718337
10413412100000
1114a366397669
1268156a61514
132cca51c9ca3
141601b562424
15ab490ee11a
hex60414807a0

413412100000 has 144 divisors (see below), whose sum is σ = 1044820611576. Its totient is φ = 160894080000.

The previous prime is 413412099979. The next prime is 413412100021. The reversal of 413412100000 is 1214314.

It is an interprime number because it is at equal distance from previous prime (413412099979) and next prime (413412100021).

It can be written as a sum of positive squares in 12 ways, for example, as 75139581456 + 338272518544 = 274116^2 + 581612^2 .

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3644134 + ... + 3755866.

Almost surely, 2413412100000 is an apocalyptic number.

413412100000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 413412100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (522410305788).

413412100000 is an abundant number, since it is smaller than the sum of its proper divisors (631408511576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

413412100000 is an equidigital number, since it uses as much as digits as its factorization.

413412100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111805 (or 111777 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 413412100000 its reverse (1214314), we get a palindrome (413413314314).

The spelling of 413412100000 in words is "four hundred thirteen billion, four hundred twelve million, one hundred thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 37 40 50 74 80 100 125 148 160 185 200 250 296 370 400 500 592 625 740 800 925 1000 1184 1250 1480 1850 2000 2500 2960 3125 3700 4000 4625 5000 5920 6250 7400 9250 10000 12500 14800 18500 20000 23125 25000 29600 37000 46250 50000 74000 92500 100000 111733 115625 148000 185000 223466 231250 370000 446932 462500 558665 740000 893864 925000 1117330 1787728 1850000 2234660 2793325 3575456 3700000 4134121 4469320 5586650 8268242 8938640 11173300 13966625 16536484 17877280 20670605 22346600 27933250 33072968 41341210 44693200 55866500 66145936 69833125 82682420 89386400 103353025 111733000 132291872 139666250 165364840 206706050 223466000 279332500 330729680 349165625 413412100 446932000 516765125 558665000 661459360 698331250 826824200 1033530250 1117330000 1396662500 1653648400 2067060500 2234660000 2583825625 2793325000 3307296800 4134121000 5167651250 5586650000 8268242000 10335302500 11173300000 12919128125 16536484000 20670605000 25838256250 41341210000 51676512500 82682420000 103353025000 206706050000 413412100000