Base | Representation |
---|---|
bin | 1100000010000010100… |
… | …10000000011110100000 |
3 | 1110112002101210122101021 |
4 | 12001001102000132200 |
5 | 23233131444200000 |
6 | 513530252015224 |
7 | 41603510604244 |
oct | 6010122003640 |
9 | 1415071718337 |
10 | 413412100000 |
11 | 14a366397669 |
12 | 68156a61514 |
13 | 2cca51c9ca3 |
14 | 1601b562424 |
15 | ab490ee11a |
hex | 60414807a0 |
413412100000 has 144 divisors (see below), whose sum is σ = 1044820611576. Its totient is φ = 160894080000.
The previous prime is 413412099979. The next prime is 413412100021. The reversal of 413412100000 is 1214314.
It is an interprime number because it is at equal distance from previous prime (413412099979) and next prime (413412100021).
It can be written as a sum of positive squares in 12 ways, for example, as 75139581456 + 338272518544 = 274116^2 + 581612^2 .
It is a Harshad number since it is a multiple of its sum of digits (16).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3644134 + ... + 3755866.
Almost surely, 2413412100000 is an apocalyptic number.
413412100000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 413412100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (522410305788).
413412100000 is an abundant number, since it is smaller than the sum of its proper divisors (631408511576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
413412100000 is an equidigital number, since it uses as much as digits as its factorization.
413412100000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111805 (or 111777 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 413412100000 its reverse (1214314), we get a palindrome (413413314314).
The spelling of 413412100000 in words is "four hundred thirteen billion, four hundred twelve million, one hundred thousand".
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