Base | Representation |
---|---|
bin | 111111001001111100001… |
… | …010001010111110000000 |
3 | 120100220022001200210001021 |
4 | 333021330022022332000 |
5 | 1032101310000310422 |
6 | 13121433554115224 |
7 | 625361150260654 |
oct | 77117412127600 |
9 | 16326261623037 |
10 | 4340000010112 |
11 | 1423646953568 |
12 | 5a115527bb14 |
13 | 25634c9b1380 |
14 | 1100b2a52a64 |
15 | 77d60153dc7 |
hex | 3f27c28af80 |
4340000010112 has 32 divisors (see below), whose sum is σ = 9311177909880. Its totient is φ = 2003076926976.
The previous prime is 4340000010061. The next prime is 4340000010119. The reversal of 4340000010112 is 2110100000434.
4340000010112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (32).
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4340000010119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1304084878 + ... + 1304088205.
Almost surely, 24340000010112 is an apocalyptic number.
It is an amenable number.
4340000010112 is an abundant number, since it is smaller than the sum of its proper divisors (4971177899768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4340000010112 is a wasteful number, since it uses less digits than its factorization.
4340000010112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2608173110 (or 2608173098 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 4340000010112 its reverse (2110100000434), we get a palindrome (6450100010546).
The spelling of 4340000010112 in words is "four trillion, three hundred forty billion, ten thousand, one hundred twelve".
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