Base | Representation |
---|---|
bin | 1110010011010000010… |
… | …10001001110011011000 |
3 | 1201222022200102111202220 |
4 | 13021220022021303120 |
5 | 31022313140420200 |
6 | 1013422313024040 |
7 | 50333462035563 |
oct | 7115012116330 |
9 | 1658280374686 |
10 | 491373763800 |
11 | 17a432752577 |
12 | 7b2940b5020 |
13 | 3744ac542ba |
14 | 19ad57034da |
15 | cbad6864a0 |
hex | 7268289cd8 |
491373763800 has 48 divisors (see below), whose sum is σ = 1523258669640. Its totient is φ = 131033003520.
The previous prime is 491373763787. The next prime is 491373763813. The reversal of 491373763800 is 8367373194.
It is an interprime number because it is at equal distance from previous prime (491373763787) and next prime (491373763813).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 409477537 + ... + 409478736.
Almost surely, 2491373763800 is an apocalyptic number.
491373763800 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
491373763800 is an abundant number, since it is smaller than the sum of its proper divisors (1031884905840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
491373763800 is a wasteful number, since it uses less digits than its factorization.
491373763800 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 818956292 (or 818956283 counting only the distinct ones).
The product of its (nonzero) digits is 2286144, while the sum is 51.
The spelling of 491373763800 in words is "four hundred ninety-one billion, three hundred seventy-three million, seven hundred sixty-three thousand, eight hundred".
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