Base | Representation |
---|---|
bin | 110111111110001011111111… |
… | …0011000000100000011101000 |
3 | 2101120012111010201210220120210 |
4 | 1233330113332120010003220 |
5 | 1004012332041404102440 |
6 | 4503034122105421120 |
7 | 205462550516444265 |
oct | 15774277630040350 |
9 | 2346174121726523 |
10 | 492332073894120 |
11 | 132965950708249 |
12 | 4727530749a7a0 |
13 | 1819393b840a05 |
14 | 8980ddc97a26c |
15 | 3bdba48d7ca80 |
hex | 1bfc5fe6040e8 |
492332073894120 has 128 divisors (see below), whose sum is σ = 1574413028352000. Its totient is φ = 122804216121600.
The previous prime is 492332073893941. The next prime is 492332073894127. The reversal of 492332073894120 is 21498370233294.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is not an unprimeable number, because it can be changed into a prime (492332073894127) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1366497856 + ... + 1366858095.
It is an arithmetic number, because the mean of its divisors is an integer number (12300101784000).
Almost surely, 2492332073894120 is an apocalyptic number.
492332073894120 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
492332073894120 is an abundant number, since it is smaller than the sum of its proper divisors (1082080954457880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
492332073894120 is a wasteful number, since it uses less digits than its factorization.
492332073894120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2733356063 (or 2733356059 counting only the distinct ones).
The product of its (nonzero) digits is 15676416, while the sum is 57.
The spelling of 492332073894120 in words is "four hundred ninety-two trillion, three hundred thirty-two billion, seventy-three million, eight hundred ninety-four thousand, one hundred twenty".
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