Base | Representation |
---|---|
bin | 100100100001100010000… |
… | …1100101011110110101111 |
3 | 122202220000102122020211202 |
4 | 1021003010030223312233 |
5 | 1124221034221231143 |
6 | 14402023115440115 |
7 | 1025445441255605 |
oct | 111030414536657 |
9 | 18686012566752 |
10 | 5019813461423 |
11 | 1665988918372 |
12 | 690a5945603b |
13 | 2a549bc18b37 |
14 | 134d62d91875 |
15 | 8a89bde1ab8 |
hex | 490c432bdaf |
5019813461423 has 2 divisors, whose sum is σ = 5019813461424. Its totient is φ = 5019813461422.
The previous prime is 5019813461363. The next prime is 5019813461483. The reversal of 5019813461423 is 3241643189105.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (5019813461363) and next prime (5019813461483).
It is a cyclic number.
It is not a de Polignac number, because 5019813461423 - 28 = 5019813461167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5019813461483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2509906730711 + 2509906730712.
It is an arithmetic number, because the mean of its divisors is an integer number (2509906730712).
Almost surely, 25019813461423 is an apocalyptic number.
5019813461423 is a deficient number, since it is larger than the sum of its proper divisors (1).
5019813461423 is an equidigital number, since it uses as much as digits as its factorization.
5019813461423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 47.
The spelling of 5019813461423 in words is "five trillion, nineteen billion, eight hundred thirteen million, four hundred sixty-one thousand, four hundred twenty-three".
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