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5110331145350 = 252248779410833
BaseRepresentation
bin100101001011101011101…
…1110001111110010000110
3200002112122202122000210212
41022113113132033302012
51132211424233122400
614511353111515422
71035131525011004
oct112272736176206
920075582560725
105110331145350
1116a0308784012
126a64bb688b72
132b0b96075362
141394ac929a74
158cde892b335
hex4a5d778fc86

5110331145350 has 24 divisors (see below), whose sum is σ = 9505277274360. Its totient is φ = 2044119265920.

The previous prime is 5110331145323. The next prime is 5110331145383. The reversal of 5110331145350 is 535411330115.

It is a super-2 number, since 2×51103311453502 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12233534 + ... + 12644366.

It is an arithmetic number, because the mean of its divisors is an integer number (396053219765).

Almost surely, 25110331145350 is an apocalyptic number.

5110331145350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

5110331145350 is a deficient number, since it is larger than the sum of its proper divisors (4394946129010).

5110331145350 is a wasteful number, since it uses less digits than its factorization.

5110331145350 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 659624 (or 659619 counting only the distinct ones).

The product of its (nonzero) digits is 13500, while the sum is 32.

Adding to 5110331145350 its reverse (535411330115), we get a palindrome (5645742475465).

The spelling of 5110331145350 in words is "five trillion, one hundred ten billion, three hundred thirty-one million, one hundred forty-five thousand, three hundred fifty".

Divisors: 1 2 5 10 25 50 248779 410833 497558 821666 1243895 2054165 2487790 4108330 6219475 10270825 12438950 20541650 102206622907 204413245814 511033114535 1022066229070 2555165572675 5110331145350