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511424062661 is a prime number
BaseRepresentation
bin1110111000100110011…
…11111110010011000101
31210220002000121020002102
413130103033332103011
531334344030001121
61030540040321445
751643364543441
oct7342317762305
91726060536072
10511424062661
111879916068a6
128314aa73285
13392c4b90375
141aa7855d821
15d483a3a90b
hex77133fe4c5

511424062661 has 2 divisors, whose sum is σ = 511424062662. Its totient is φ = 511424062660.

The previous prime is 511424062637. The next prime is 511424062663. The reversal of 511424062661 is 166260424115.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 488230600225 + 23193462436 = 698735^2 + 152294^2 .

It is a cyclic number.

It is not a de Polignac number, because 511424062661 - 210 = 511424061637 is a prime.

Together with 511424062663, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511424062663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255712031330 + 255712031331.

It is an arithmetic number, because the mean of its divisors is an integer number (255712031331).

Almost surely, 2511424062661 is an apocalyptic number.

It is an amenable number.

511424062661 is a deficient number, since it is larger than the sum of its proper divisors (1).

511424062661 is an equidigital number, since it uses as much as digits as its factorization.

511424062661 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 38.

Adding to 511424062661 its reverse (166260424115), we get a palindrome (677684486776).

The spelling of 511424062661 in words is "five hundred eleven billion, four hundred twenty-four million, sixty-two thousand, six hundred sixty-one".