Base | Representation |
---|---|
bin | 1110111001110001101… |
… | …11111101111101000000 |
3 | 1210221201000101121102021 |
4 | 13130320313331331000 |
5 | 31342142124212000 |
6 | 1031122430131224 |
7 | 51665131161262 |
oct | 7347067757500 |
9 | 1727630347367 |
10 | 512055304000 |
11 | 188185962859 |
12 | 832a6350b14 |
13 | 393958a6c56 |
14 | 1aad8319b32 |
15 | d4be17a11a |
hex | 7738dfdf40 |
512055304000 has 56 divisors (see below), whose sum is σ = 1268104980168. Its totient is φ = 204822118400.
The previous prime is 512055303967. The next prime is 512055304009. The reversal of 512055304000 is 403550215.
It can be written as a sum of positive squares in 4 ways, for example, as 338265664 + 511717038336 = 18392^2 + 715344^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (512055304009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31995457 + ... + 32011456.
Almost surely, 2512055304000 is an apocalyptic number.
512055304000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
512055304000 is an abundant number, since it is smaller than the sum of its proper divisors (756049676168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
512055304000 is an equidigital number, since it uses as much as digits as its factorization.
512055304000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64006940 (or 64006920 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 25.
Adding to 512055304000 its reverse (403550215), we get a palindrome (512458854215).
The spelling of 512055304000 in words is "five hundred twelve billion, fifty-five million, three hundred four thousand".
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