Base | Representation |
---|---|
bin | 100101010010100100010… |
… | …0011001000100000001110 |
3 | 200010221210221120211222001 |
4 | 1022211020203020200032 |
5 | 1132432212431403200 |
6 | 14522240001342514 |
7 | 1036164040006555 |
oct | 112451043104016 |
9 | 20127727524861 |
10 | 5125113153550 |
11 | 16a6603844615 |
12 | 6a9346037a3a |
13 | 2b23b06a7a80 |
14 | 13a0b1c06d9c |
15 | 8d4b153076a |
hex | 4a9488c880e |
5125113153550 has 96 divisors (see below), whose sum is σ = 10285216704000. Its totient is φ = 1888810224000.
The previous prime is 5125113153547. The next prime is 5125113153557. The reversal of 5125113153550 is 553513115215.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125113153557) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 957783375 + ... + 957788725.
It is an arithmetic number, because the mean of its divisors is an integer number (107137674000).
Almost surely, 25125113153550 is an apocalyptic number.
5125113153550 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5125113153550 is an abundant number, since it is smaller than the sum of its proper divisors (5160103550450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5125113153550 is a wasteful number, since it uses less digits than its factorization.
5125113153550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7858 (or 7853 counting only the distinct ones).
The product of its (nonzero) digits is 56250, while the sum is 37.
Adding to 5125113153550 its reverse (553513115215), we get a palindrome (5678626268765).
The spelling of 5125113153550 in words is "five trillion, one hundred twenty-five billion, one hundred thirteen million, one hundred fifty-three thousand, five hundred fifty".
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