Base | Representation |
---|---|
bin | 10111010011101010001011… |
… | …00110101100110111111110 |
3 | 20201110201222120021020021210 |
4 | 23221311011212230313332 |
5 | 23204212132201010400 |
6 | 301001150420105250 |
7 | 13536623300162331 |
oct | 1351650546546776 |
9 | 221421876236253 |
10 | 51253012516350 |
11 | 1537030a447367 |
12 | 58b9216235226 |
13 | 227a1a4c24c48 |
14 | c929325a6618 |
15 | 5dd31d907950 |
hex | 2e9d459acdfe |
51253012516350 has 24 divisors (see below), whose sum is σ = 127107471040920. Its totient is φ = 13667470004320.
The previous prime is 51253012516313. The next prime is 51253012516379. The reversal of 51253012516350 is 5361521035215.
It is a super-2 number, since 2×512530125163502 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51253012516299 and 51253012516308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 170843374905 + ... + 170843375204.
It is an arithmetic number, because the mean of its divisors is an integer number (5296144626705).
Almost surely, 251253012516350 is an apocalyptic number.
51253012516350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
51253012516350 is an abundant number, since it is smaller than the sum of its proper divisors (75854458524570).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51253012516350 is a wasteful number, since it uses less digits than its factorization.
51253012516350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 341686750124 (or 341686750119 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 39.
The spelling of 51253012516350 in words is "fifty-one trillion, two hundred fifty-three billion, twelve million, five hundred sixteen thousand, three hundred fifty".
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