51411300 has 72 divisors (see below), whose sum is σ = 149469600. Its totient is φ = 13643520.

The previous prime is 51411293. The next prime is 51411301. The reversal of 51411300 is 311415.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 51411300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51411301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 122491 + ... + 122909.

Almost surely, 2^51411300 is an apocalyptic number.

51411300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 51411300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (74734800).

51411300 is an abundant number, since it is smaller than the sum of its proper divisors (98058300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51411300 is a wasteful number, since it uses less digits than its factorization.

51411300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 845 (or 838 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 51411300 is about 7170.1673620635. The cubic root of 51411300 is about 371.8372221116.

Adding to 51411300 its reverse (311415), we get a palindrome (51722715).

It can be divided in two parts, 5141 and 1300, that added together give a triangular number (6441 = T₁₁₃).

The spelling of 51411300 in words is "fifty-one million, four hundred eleven thousand, three hundred".