52107030 has 64 divisors (see below), whose sum is σ = 141350400. Its totient is φ = 13655520.

The previous prime is 52107017. The next prime is 52107037. The reversal of 52107030 is 3070125.

52107030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an alternating number because its digits alternate between odd and even.

It is a junction number, because it is equal to n+sod(n) for n = 52106994 and 52107012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52107037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14295 + ... + 17565.

It is an arithmetic number, because the mean of its divisors is an integer number (2208600).

Almost surely, 2^52107030 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 52107030, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (70675200).

52107030 is an abundant number, since it is smaller than the sum of its proper divisors (89243370).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

52107030 is a wasteful number, since it uses less digits than its factorization.

52107030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3346 (or 3340 counting only the distinct ones).

The product of its (nonzero) digits is 210, while the sum is 18.

The square root of 52107030 is about 7218.5199313987. The cubic root of 52107030 is about 373.5070239482.

Adding to 52107030 its reverse (3070125), we get a palindrome (55177155).

The spelling of 52107030 in words is "fifty-two million, one hundred seven thousand, thirty".