Base | Representation |
---|---|
bin | 11000000111110001001110… |
… | …00110001000000110000000 |
3 | 20221210220112212011021120111 |
4 | 30003320213012020012000 |
5 | 23423031043004214130 |
6 | 304451503132121104 |
7 | 14113160266652554 |
oct | 1403704706100600 |
9 | 227726485137514 |
10 | 53043502023040 |
11 | 159a0694061621 |
12 | 5b48229606194 |
13 | 2379c999cc7c9 |
14 | d15467c35864 |
15 | 61ebb354702a |
hex | 303e27188180 |
53043502023040 has 32 divisors (see below), whose sum is σ = 126807122025360. Its totient is φ = 21217400808960.
The previous prime is 53043502023037. The next prime is 53043502023067. The reversal of 53043502023040 is 4032020534035.
It is a tau number, because it is divible by the number of its divisors (32).
It is a super-2 number, since 2×530435020230402 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53043502022993 and 53043502023011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41440235316 + ... + 41440236595.
Almost surely, 253043502023040 is an apocalyptic number.
It is an amenable number.
53043502023040 is an abundant number, since it is smaller than the sum of its proper divisors (73763620002320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53043502023040 is an equidigital number, since it uses as much as digits as its factorization.
53043502023040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82880471930 (or 82880471918 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 31.
Adding to 53043502023040 its reverse (4032020534035), we get a palindrome (57075522557075).
The spelling of 53043502023040 in words is "fifty-three trillion, forty-three billion, five hundred two million, twenty-three thousand, forty".
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