Base | Representation |
---|---|
bin | 110001011101101010… |
… | …111011010000011000 |
3 | 12002002101222112022010 |
4 | 301131222323100120 |
5 | 1332232423011100 |
6 | 40222100025520 |
7 | 3560100152562 |
oct | 613552732030 |
9 | 162071875263 |
10 | 53111141400 |
11 | 20584944699 |
12 | a3629922a0 |
13 | 5015498cb5 |
14 | 27db9c8332 |
15 | 15aca8e750 |
hex | c5dabb418 |
53111141400 has 48 divisors (see below), whose sum is σ = 164644540200. Its totient is φ = 14162970880.
The previous prime is 53111141399. The next prime is 53111141431. The reversal of 53111141400 is 414111135.
53111141400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44258685 + ... + 44259884.
Almost surely, 253111141400 is an apocalyptic number.
53111141400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53111141400 is an abundant number, since it is smaller than the sum of its proper divisors (111533398800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53111141400 is a wasteful number, since it uses less digits than its factorization.
53111141400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88518588 (or 88518579 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 53111141400 its reverse (414111135), we get a palindrome (53525252535).
The spelling of 53111141400 in words is "fifty-three billion, one hundred eleven million, one hundred forty-one thousand, four hundred".
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