Base | Representation |
---|---|
bin | 110001011101110011… |
… | …010111001100101000 |
3 | 12002002120010220001020 |
4 | 301131303113030220 |
5 | 1332234004244000 |
6 | 40222215252440 |
7 | 3560125023441 |
oct | 613563271450 |
9 | 162076126036 |
10 | 53113353000 |
11 | 20586115264 |
12 | a36367a120 |
13 | 5015a91836 |
14 | 27dc0022c8 |
15 | 15acd79ba0 |
hex | c5dcd7328 |
53113353000 has 64 divisors (see below), whose sum is σ = 165713670720. Its totient is φ = 14163560000.
The previous prime is 53113352993. The next prime is 53113353019. The reversal of 53113353000 is 35331135.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8849226 + ... + 8855225.
It is an arithmetic number, because the mean of its divisors is an integer number (2589276105).
Almost surely, 253113353000 is an apocalyptic number.
53113353000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53113353000 is an abundant number, since it is smaller than the sum of its proper divisors (112600317720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53113353000 is a wasteful number, since it uses less digits than its factorization.
53113353000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17704475 (or 17704461 counting only the distinct ones).
The product of its (nonzero) digits is 2025, while the sum is 24.
Adding to 53113353000 its reverse (35331135), we get a palindrome (53148684135).
The spelling of 53113353000 in words is "fifty-three billion, one hundred thirteen million, three hundred fifty-three thousand".
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