Base | Representation |
---|---|
bin | 100110101011110010001… |
… | …0000101011100001111000 |
3 | 200211021100020210112010112 |
4 | 1031113210100223201320 |
5 | 1144102102223414000 |
6 | 15150243221003452 |
7 | 1056055612250534 |
oct | 115274420534170 |
9 | 20737306715115 |
10 | 5316704123000 |
11 | 176a88a964696 |
12 | 71a4b5553588 |
13 | 2c749480000a |
14 | 145489188bc4 |
15 | 93476610235 |
hex | 4d5e442b878 |
5316704123000 has 64 divisors (see below), whose sum is σ = 12441514381920. Its totient is φ = 2126608704000.
The previous prime is 5316704122957. The next prime is 5316704123063. The reversal of 5316704123000 is 3214076135.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36360035 + ... + 36505965.
Almost surely, 25316704123000 is an apocalyptic number.
5316704123000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5316704123000 is an abundant number, since it is smaller than the sum of its proper divisors (7124810258920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5316704123000 is a wasteful number, since it uses less digits than its factorization.
5316704123000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182385 (or 182371 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 5316704123000 its reverse (3214076135), we get a palindrome (5319918199135).
The spelling of 5316704123000 in words is "five trillion, three hundred sixteen billion, seven hundred four million, one hundred twenty-three thousand".
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