Base | Representation |
---|---|
bin | 110001100010001010… |
… | …010100101001101110 |
3 | 12002021122202011110102 |
4 | 301202022110221232 |
5 | 1332411214341000 |
6 | 40233350511102 |
7 | 3562003425044 |
oct | 614212245156 |
9 | 162248664412 |
10 | 53186480750 |
11 | 20613422217 |
12 | a384065492 |
13 | 5027c86bb0 |
14 | 28079da394 |
15 | 15b44c23d5 |
hex | c62294a6e |
53186480750 has 128 divisors (see below), whose sum is σ = 110139015168. Its totient is φ = 19109136000.
The previous prime is 53186480741. The next prime is 53186480779. The reversal of 53186480750 is 5708468135.
It is a hoax number, since the sum of its digits (47) coincides with the sum of the digits of its distinct prime factors.
It is a Harshad number since it is a multiple of its sum of digits (47).
It is a junction number, because it is equal to n+sod(n) for n = 53186480695 and 53186480704.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 29174339 + ... + 29176161.
It is an arithmetic number, because the mean of its divisors is an integer number (860461056).
Almost surely, 253186480750 is an apocalyptic number.
53186480750 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53186480750 is an abundant number, since it is smaller than the sum of its proper divisors (56952534418).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53186480750 is a wasteful number, since it uses less digits than its factorization.
53186480750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2091 (or 2081 counting only the distinct ones).
The product of its (nonzero) digits is 806400, while the sum is 47.
The spelling of 53186480750 in words is "fifty-three billion, one hundred eighty-six million, four hundred eighty thousand, seven hundred fifty".
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