Base | Representation |
---|---|
bin | 110001100010100000… |
… | …111001001001011000 |
3 | 12002022001212202120121 |
4 | 301202200321021120 |
5 | 1332414223204100 |
6 | 40234121403024 |
7 | 3562104626542 |
oct | 614240711130 |
9 | 162261782517 |
10 | 53192397400 |
11 | 206167a350a |
12 | a386039474 |
13 | 5029278c7c |
14 | 28086da692 |
15 | 15b4c9051a |
hex | c62839258 |
53192397400 has 96 divisors (see below), whose sum is σ = 129205011600. Its totient is φ = 20339648000.
The previous prime is 53192397373. The next prime is 53192397409. The reversal of 53192397400 is 479329135.
It is a super-2 number, since 2×531923974002 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53192397409) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 540399 + ... + 631201.
Almost surely, 253192397400 is an apocalyptic number.
53192397400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53192397400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (64602505800).
53192397400 is an abundant number, since it is smaller than the sum of its proper divisors (76012614200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53192397400 is a wasteful number, since it uses less digits than its factorization.
53192397400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90949 (or 90940 counting only the distinct ones).
The product of its (nonzero) digits is 204120, while the sum is 43.
The spelling of 53192397400 in words is "fifty-three billion, one hundred ninety-two million, three hundred ninety-seven thousand, four hundred".
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