Base | Representation |
---|---|
bin | 111100100001001011010101… |
… | …1001001110010111110001110 |
3 | 2120210210210221022021210201022 |
4 | 1321002112223021302332032 |
5 | 1024233104421223334200 |
6 | 5124054530242114142 |
7 | 220061145660663341 |
oct | 17102265311627616 |
9 | 2523723838253638 |
10 | 532325413105550 |
11 | 144684a38004279 |
12 | 4b85429394b952 |
13 | 19b050c017bc5c |
14 | 956498a598458 |
15 | 4182013e37885 |
hex | 1e425ab272f8e |
532325413105550 has 24 divisors (see below), whose sum is σ = 992070504707400. Its totient is φ = 212511834848480.
The previous prime is 532325413105517. The next prime is 532325413105579. The reversal of 532325413105550 is 55501314523235.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10458234140 + ... + 10458285039.
It is an arithmetic number, because the mean of its divisors is an integer number (41336271029475).
Almost surely, 2532325413105550 is an apocalyptic number.
532325413105550 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
532325413105550 is a deficient number, since it is larger than the sum of its proper divisors (459745091601850).
532325413105550 is a wasteful number, since it uses less digits than its factorization.
532325413105550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20916519700 (or 20916519695 counting only the distinct ones).
The product of its (nonzero) digits is 1350000, while the sum is 44.
Adding to 532325413105550 its reverse (55501314523235), we get a palindrome (587826727628785).
The spelling of 532325413105550 in words is "five hundred thirty-two trillion, three hundred twenty-five billion, four hundred thirteen million, one hundred five thousand, five hundred fifty".
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