Base | Representation |
---|---|
bin | 100110110111001001100… |
… | …1110000111101010111010 |
3 | 200220121100102212001102102 |
4 | 1031232103032013222322 |
5 | 1200002100230113424 |
6 | 15205401331503402 |
7 | 1060611535323554 |
oct | 115562316075272 |
9 | 20817312761372 |
10 | 5341114301114 |
11 | 177a176864809 |
12 | 723188457b62 |
13 | 2c9884a925a7 |
14 | 1467230784d4 |
15 | 93e046257ae |
hex | 4db93387aba |
5341114301114 has 96 divisors (see below), whose sum is σ = 8903605556736. Its totient is φ = 2397994204320.
The previous prime is 5341114301087. The next prime is 5341114301129. The reversal of 5341114301114 is 4111034111435.
It is a happy number.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1973073749 + ... + 1973076455.
It is an arithmetic number, because the mean of its divisors is an integer number (92745891216).
Almost surely, 25341114301114 is an apocalyptic number.
5341114301114 is a deficient number, since it is larger than the sum of its proper divisors (3562491255622).
5341114301114 is a wasteful number, since it uses less digits than its factorization.
5341114301114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3808 (or 3789 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 5341114301114 its reverse (4111034111435), we get a palindrome (9452148412549).
The spelling of 5341114301114 in words is "five trillion, three hundred forty-one billion, one hundred fourteen million, three hundred one thousand, one hundred fourteen".
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