Base | Representation |
---|---|
bin | 100111010111110101111… |
… | …1000100111001111101000 |
3 | 201011022120021201202011110 |
4 | 1032233223320213033220 |
5 | 1202124341223442412 |
6 | 15301532055430320 |
7 | 1065645405141303 |
oct | 116575370471750 |
9 | 21138507652143 |
10 | 5411321312232 |
11 | 17a6a23898350 |
12 | 7349006853a0 |
13 | 30339307a514 |
14 | 149ca3379b3a |
15 | 95b62ec7d3c |
hex | 4ebebe273e8 |
5411321312232 has 64 divisors (see below), whose sum is σ = 14896075737600. Its totient is φ = 1624469147840.
The previous prime is 5411321312231. The next prime is 5411321312237. The reversal of 5411321312232 is 2322131231145.
It is a super-3 number, since 3×54113213122323 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5411321312232.
It is not an unprimeable number, because it can be changed into a prime (5411321312231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95754132 + ... + 95810627.
It is an arithmetic number, because the mean of its divisors is an integer number (232751183400).
Almost surely, 25411321312232 is an apocalyptic number.
It is an amenable number.
5411321312232 is an abundant number, since it is smaller than the sum of its proper divisors (9484754425368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5411321312232 is a wasteful number, since it uses less digits than its factorization.
5411321312232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191564886 (or 191564882 counting only the distinct ones).
The product of its digits is 8640, while the sum is 30.
Adding to 5411321312232 its reverse (2322131231145), we get a palindrome (7733452543377).
The spelling of 5411321312232 in words is "five trillion, four hundred eleven billion, three hundred twenty-one million, three hundred twelve thousand, two hundred thirty-two".
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