Base | Representation |
---|---|
bin | 111101100010110010000111… |
… | …0010000000010101100011100 |
3 | 2121222201210212112020222221121 |
4 | 1323011210032100002230130 |
5 | 1031423322322240312000 |
6 | 5155201102400140324 |
7 | 222011453444234362 |
oct | 17305441620025434 |
9 | 2558653775228847 |
10 | 541342212041500 |
11 | 147540a40a31641 |
12 | 5086b8b76076a4 |
13 | 1a30a47549461c |
14 | 9797162381632 |
15 | 428b847321b1a |
hex | 1ec590e402b1c |
541342212041500 has 24 divisors (see below), whose sum is σ = 1182291391099728. Its totient is φ = 216536884816400.
The previous prime is 541342212041497. The next prime is 541342212041549. The reversal of 541342212041500 is 5140212243145.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 541342211542 + ... + 541342212541.
It is an arithmetic number, because the mean of its divisors is an integer number (49262141295822).
Almost surely, 2541342212041500 is an apocalyptic number.
541342212041500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
541342212041500 is an abundant number, since it is smaller than the sum of its proper divisors (640949179058228).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
541342212041500 is a wasteful number, since it uses less digits than its factorization.
541342212041500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1082684424102 (or 1082684424090 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 541342212041500 its reverse (5140212243145), we get a palindrome (546482424284645).
The spelling of 541342212041500 in words is "five hundred forty-one trillion, three hundred forty-two billion, two hundred twelve million, forty-one thousand, five hundred".
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