Base | Representation |
---|---|
bin | 101000000001011000101… |
… | …0100101011000010110100 |
3 | 201110211211121111102002012 |
4 | 1100002301110223002310 |
5 | 1210110042440002200 |
6 | 15410524322303352 |
7 | 1105254224061623 |
oct | 120026124530264 |
9 | 21424747442065 |
10 | 5500533125300 |
11 | 1830843606984 |
12 | 74a0594b7b58 |
13 | 30b90c7c47a5 |
14 | 1503277056ba |
15 | 98135062a35 |
hex | 500b152b0b4 |
5500533125300 has 36 divisors (see below), whose sum is σ = 12016265349900. Its totient is φ = 2185446712320.
The previous prime is 5500533125291. The next prime is 5500533125359. The reversal of 5500533125300 is 35213350055.
It can be written as a sum of positive squares in 6 ways, for example, as 1901150107684 + 3599383017616 = 1378822^2 + 1897204^2 .
It is a super-3 number, since 3×55005331253003 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 184566749 + ... + 184596548.
Almost surely, 25500533125300 is an apocalyptic number.
5500533125300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5500533125300 is an abundant number, since it is smaller than the sum of its proper divisors (6515732224600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5500533125300 is a wasteful number, since it uses less digits than its factorization.
5500533125300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 369163460 (or 369163453 counting only the distinct ones).
The product of its (nonzero) digits is 33750, while the sum is 32.
Adding to 5500533125300 its reverse (35213350055), we get a palindrome (5535746475355).
The spelling of 5500533125300 in words is "five trillion, five hundred billion, five hundred thirty-three million, one hundred twenty-five thousand, three hundred".
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