Base | Representation |
---|---|
bin | 11001000001011001011110… |
… | …01010010110011000000100 |
3 | 21012211012120111100002011220 |
4 | 30200230233022112120010 |
5 | 24203001332010140200 |
6 | 313005300102000340 |
7 | 14406216346604526 |
oct | 1440545712263004 |
9 | 235735514302156 |
10 | 55023617271300 |
11 | 1659442653a087 |
12 | 6207b421160b0 |
13 | 249192170b392 |
14 | d8322b83da16 |
15 | 6564559714a0 |
hex | 320b2f296604 |
55023617271300 has 72 divisors (see below), whose sum is σ = 168566469867936. Its totient is φ = 13809849039360.
The previous prime is 55023617271209. The next prime is 55023617271331. The reversal of 55023617271300 is 317271632055.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5394467182 + ... + 5394477381.
It is an arithmetic number, because the mean of its divisors is an integer number (2341200970388).
Almost surely, 255023617271300 is an apocalyptic number.
55023617271300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
55023617271300 is an abundant number, since it is smaller than the sum of its proper divisors (113542852596636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55023617271300 is a wasteful number, since it uses less digits than its factorization.
55023617271300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10788944597 (or 10788944590 counting only the distinct ones).
The product of its (nonzero) digits is 264600, while the sum is 42.
The spelling of 55023617271300 in words is "fifty-five trillion, twenty-three billion, six hundred seventeen million, two hundred seventy-one thousand, three hundred".
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