Base | Representation |
---|---|
bin | 111110101010111000110001… |
… | …0011011111101100001001000 |
3 | 2200021211012001122010201112121 |
4 | 1331111301202123331201020 |
5 | 1034223203312141112130 |
6 | 5232225420343421024 |
7 | 224053436163125641 |
oct | 17525614233754110 |
9 | 2607735048121477 |
10 | 551252114004040 |
11 | 14a711788273579 |
12 | 519b0429754774 |
13 | 1a878b0b3c3437 |
14 | 9a1aa5d5726c8 |
15 | 43ae4ec4bed7a |
hex | 1f55c626fd848 |
551252114004040 has 32 divisors (see below), whose sum is σ = 1261339582896000. Its totient is φ = 216763543132864.
The previous prime is 551252114003989. The next prime is 551252114004139. The reversal of 551252114004040 is 40400411252155.
It is a super-2 number, since 2×5512521140040402 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 551252114003987 and 551252114004005.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116790699760 + ... + 116790704479.
It is an arithmetic number, because the mean of its divisors is an integer number (39416861965500).
Almost surely, 2551252114004040 is an apocalyptic number.
It is an amenable number.
551252114004040 is an abundant number, since it is smaller than the sum of its proper divisors (710087468891960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
551252114004040 is a wasteful number, since it uses less digits than its factorization.
551252114004040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233581404309 (or 233581404305 counting only the distinct ones).
The product of its (nonzero) digits is 32000, while the sum is 34.
Adding to 551252114004040 its reverse (40400411252155), we get a palindrome (591652525256195).
The spelling of 551252114004040 in words is "five hundred fifty-one trillion, two hundred fifty-two billion, one hundred fourteen million, four thousand, forty".
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