Base | Representation |
---|---|
bin | 111110110010001001100110… |
… | …0011001010101111101101110 |
3 | 2200102100121121121120101021110 |
4 | 1331210103030121111331232 |
5 | 1034341032130433142220 |
6 | 5234312144014412450 |
7 | 224215524565102332 |
oct | 17544231431257556 |
9 | 2612317547511243 |
10 | 552250324115310 |
11 | 14aa67057910587 |
12 | 51b31990201126 |
13 | 1a91bc9c8cc302 |
14 | 9a530b5db57c2 |
15 | 43ca471a28be0 |
hex | 1f644cc655f6e |
552250324115310 has 32 divisors (see below), whose sum is σ = 1337129988308640. Its totient is φ = 145963507493888.
The previous prime is 552250324115251. The next prime is 552250324115317. The reversal of 552250324115310 is 13511423052255.
It is a super-2 number, since 2×5522503241153102 (a number of 30 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (552250324115317) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81452846775 + ... + 81452853554.
It is an arithmetic number, because the mean of its divisors is an integer number (41785312134645).
Almost surely, 2552250324115310 is an apocalyptic number.
552250324115310 is an abundant number, since it is smaller than the sum of its proper divisors (784879664193330).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
552250324115310 is a wasteful number, since it uses less digits than its factorization.
552250324115310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162905700452.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 552250324115310 its reverse (13511423052255), we get a palindrome (565761747167565).
The spelling of 552250324115310 in words is "five hundred fifty-two trillion, two hundred fifty billion, three hundred twenty-four million, one hundred fifteen thousand, three hundred ten".
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