Base | Representation |
---|---|
bin | 111110111011011001011001… |
… | …1011010100011000001001100 |
3 | 2200120212010000012120211022210 |
4 | 1331312302303122203001030 |
5 | 1040022342422110221030 |
6 | 5241124045203510420 |
7 | 224406405502103004 |
oct | 17566626332430114 |
9 | 2616763005524283 |
10 | 553521215320140 |
11 | 150407035864061 |
12 | 520b8153088410 |
13 | 1a9b1a991689a2 |
14 | 9a987d9623004 |
15 | 43ed5551b5bb0 |
hex | 1f76cb36a304c |
553521215320140 has 96 divisors (see below), whose sum is σ = 1665520552571904. Its totient is φ = 136849494481920.
The previous prime is 553521215320127. The next prime is 553521215320141. The reversal of 553521215320140 is 41023512125355.
It is not an unprimeable number, because it can be changed into a prime (553521215320141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4049691796 + ... + 4049828475.
It is an arithmetic number, because the mean of its divisors is an integer number (17349172422624).
Almost surely, 2553521215320140 is an apocalyptic number.
It is an amenable number.
553521215320140 is an abundant number, since it is smaller than the sum of its proper divisors (1111999337251764).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
553521215320140 is a wasteful number, since it uses less digits than its factorization.
553521215320140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8099520367 (or 8099520365 counting only the distinct ones).
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 553521215320140 its reverse (41023512125355), we get a palindrome (594544727445495).
The spelling of 553521215320140 in words is "five hundred fifty-three trillion, five hundred twenty-one billion, two hundred fifteen million, three hundred twenty thousand, one hundred forty".
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