Base | Representation |
---|---|
bin | 110110011010001011… |
… | …010000011011101000 |
3 | 12120210110211022121210 |
4 | 312122023100123220 |
5 | 1424121312421000 |
6 | 42501025233120 |
7 | 4135506102546 |
oct | 663213203350 |
9 | 176713738553 |
10 | 58421217000 |
11 | 2285a288023 |
12 | b3a51927a0 |
13 | 5680642773 |
14 | 2b82d22d96 |
15 | 17bdd45350 |
hex | d9a2d06e8 |
58421217000 has 64 divisors (see below), whose sum is σ = 182274206400. Its totient is φ = 15578990400.
The previous prime is 58421216993. The next prime is 58421217031. The reversal of 58421217000 is 71212485.
It is a super-2 number, since 2×584212170002 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9733870 + ... + 9739869.
It is an arithmetic number, because the mean of its divisors is an integer number (2848034475).
Almost surely, 258421217000 is an apocalyptic number.
58421217000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
58421217000 is an abundant number, since it is smaller than the sum of its proper divisors (123852989400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
58421217000 is a wasteful number, since it uses less digits than its factorization.
58421217000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19473763 (or 19473749 counting only the distinct ones).
The product of its (nonzero) digits is 4480, while the sum is 30.
Adding to 58421217000 its reverse (71212485), we get a palindrome (58492429485).
The spelling of 58421217000 in words is "fifty-eight billion, four hundred twenty-one million, two hundred seventeen thousand".
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