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75143134086047 is a prime number
BaseRepresentation
bin10001000101011110011111…
…110100001000001110011111
3100212001121120012202211202222
4101011132133310020032133
534322121114311223142
6423452140152135555
721553624625036456
oct2105363764101637
9325047505684688
1075143134086047
1121a4102a239a85
1285172ab6975bb
1332c0c75a60a31
14147ad38b87b9d
158a49a3166bd2
hex44579fd0839f

75143134086047 has 2 divisors, whose sum is σ = 75143134086048. Its totient is φ = 75143134086046.

The previous prime is 75143134086037. The next prime is 75143134086049. The reversal of 75143134086047 is 74068043134157.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-75143134086047 is a prime.

Together with 75143134086049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 75143134086047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (75143134086049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37571567043023 + 37571567043024.

It is an arithmetic number, because the mean of its divisors is an integer number (37571567043024).

Almost surely, 275143134086047 is an apocalyptic number.

75143134086047 is a deficient number, since it is larger than the sum of its proper divisors (1).

75143134086047 is an equidigital number, since it uses as much as digits as its factorization.

75143134086047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6773760, while the sum is 53.

The spelling of 75143134086047 in words is "seventy-five trillion, one hundred forty-three billion, one hundred thirty-four million, eighty-six thousand, forty-seven".