Base | Representation |
---|---|
bin | 1001001100100111101010… |
… | …1111010101010101110000 |
3 | 1022210201220101200212221100 |
4 | 2103021322233111111300 |
5 | 2311140210013241222 |
6 | 33301324505324400 |
7 | 2062412000553141 |
oct | 223117257252560 |
9 | 38721811625840 |
10 | 10112412243312 |
11 | 3249717099245 |
12 | 1173a2a496700 |
13 | 58479a339a22 |
14 | 26d62c83bac8 |
15 | 1280a8bce4ac |
hex | 9327abd5570 |
10112412243312 has 30 divisors (see below), whose sum is σ = 28300709264672. Its totient is φ = 3370804081056.
The previous prime is 10112412243301. The next prime is 10112412243331. The reversal of 10112412243312 is 21334221421101.
10112412243312 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 2 + 412 + 243 + 3 + 1 + 2 = 666.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 35112542368 + ... + 35112542655.
Almost surely, 210112412243312 is an apocalyptic number.
10112412243312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
10112412243312 is an abundant number, since it is smaller than the sum of its proper divisors (18188297021360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10112412243312 is a wasteful number, since it uses less digits than its factorization.
10112412243312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70225085037 (or 70225085028 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 10112412243312 its reverse (21334221421101), we get a palindrome (31446633664413).
The spelling of 10112412243312 in words is "ten trillion, one hundred twelve billion, four hundred twelve million, two hundred forty-three thousand, three hundred twelve".
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