10113001222000 has 80 divisors (see below), whose sum is σ = 24464733040800. Its totient is φ = 4043298739200.

The previous prime is 10113001221989. The next prime is 10113001222043. The reversal of 10113001222000 is 22210031101.

It is a tau number, because it is divible by the number of its divisors (80).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3070471 + ... + 5445529.

It is an arithmetic number, because the mean of its divisors is an integer number (305809163010).

Almost surely, 2^{10113001222000} is an apocalyptic number.

10113001222000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10113001222000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12232366520400).

10113001222000 is an abundant number, since it is smaller than the sum of its proper divisors (14351731818800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10113001222000 is a wasteful number, since it uses less digits than its factorization.

10113001222000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2377211 (or 2377195 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10113001222000 its reverse (22210031101), we get a palindrome (10135211253101).

The spelling of 10113001222000 in words is "ten trillion, one hundred thirteen billion, one million, two hundred twenty-two thousand".