101433121400 has 384 divisors, whose sum is σ = 278914648320. Its totient is φ = 33961697280.

The previous prime is 101433121397. The next prime is 101433121463. The reversal of 101433121400 is 4121334101.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 157749479 + ... + 157750121.

It is an arithmetic number, because the mean of its divisors is an integer number (726340230).

Almost surely, 2^101433121400 is an apocalyptic number.

101433121400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101433121400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (139457324160).

101433121400 is an abundant number, since it is smaller than the sum of its proper divisors (177481526920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101433121400 is a wasteful number, since it uses less digits than its factorization.

101433121400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 815 (or 806 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 101433121400 its reverse (4121334101), we get a palindrome (105554455501).

The spelling of 101433121400 in words is "one hundred one billion, four hundred thirty-three million, one hundred twenty-one thousand, four hundred".